Q: Complete the following word analogy: Add is to Subtract as Multiply
is to:
1) Divide
2) ROUND
3) RANDOM
4) On a Pentium, all of the above
A: Number 4.
is to:
1) Divide
2) ROUND
3) RANDOM
4) On a Pentium, all of the above
A: Number 4.
Related:
- 1) X=Y ; Given
2) X^2=XY ; Multiply both sides by X
3) X^2-Y^2=XY-Y^2 ;
Subtract Y^2 from both sides 4) (X+Y)(X-Y)=Y(X-Y) ... - 1) X=Y ; Given
2) X^2=XY ;
Multiply both sides by X 3) X^2-Y^2=XY-Y^2 ... - define BITCOUNT(x) (((BX_(x)+(BX_(x)>>4)) & 0x0F0F0F0F) % 255)
#define BX_(x) ((x) -
(((x)>>1)&0x77777777) \ - (((x)>>2)&0x33333333)... - 1] Alexander the Great was a great general.
[2] Great generals are forewarned.
[3] Forewarned is forearmed. [4] Four is an even number... - declare foo as pointer to function returning pointer to function
returning pointer to array 3 of pointer to function returning
pointer to array 4 of array 2 of pointer to pointer to function
returning pointer to array 5 of pointer to pointer to char
char **(*(**(*(*(*(*(*foo)())())[3])())[4][2])())[5]
To turn the above into a cast,
remove the name `foo' and add (): (char... - define BITCOUNT(x) (((BX_(x)+(BX_(x)>>4)) & 0x0F0F0F0F) % 255)
#define BX_(x) ((x) -
(((x)>>1)&0x77777777) \ - (((x)>>2)&0x33333333)... - define BITCOUNT(x) (((BX_(x)+(BX_(x)>>4)) & 0x0F0F0F0F) % 255)
#define BX_(x) ((x) -
(((x)>>1)&0x77777777) \ ... - The Following Subsume All Physical and Human Laws:
1.
You can't push on a string. 2. Ain't no free lunches... - Unix will self-destruct in five seconds... 4... 3..
2... 1.....
