1. A is A.

2. A is not not-A.

does it also imply that:

1. B is B.

2. B is not not-B.

Shlomi Fish

- a = b
a*a = b*a
a*a - b*b = b*a - b*b
(a-b)*(a+b) = b(a-b)
a+b = b
b+b = b
2b = b
2 = 1
Hi

whatever number, multiplied by 0 gives 0... -- Antonio... - To be or not to be, that is the square root of 4 B^2.
- How many
school teachers
-- does it take to change a light bulb?

Let's see: 2 A+'s, 3 A's, 5 A-'s, 11 B+'s, 9 B's, 21 B-'s...... - Prior Laws of Politics: 1) Pay your dues. 2) Attend the meetings. -- Lyndon B. Johnso
- How about some patent on "(a+b)^2 == a^2 + 2ab + b^2"?

Choose free software! -- Laurent Szyste... - Theorem: All positive integers are equal.
Proof: Sufficient to show that for any two positive integers, A and B, A = B.

Further, it is sufficient to show that for all N > 0, if A and B (positive integers) satisfy (MAX(A, B) = N) then A = B.... - drugged: adj. (also `on drugs') 1. Conspicuously stupid,
heading toward {brain-damaged}.

Often accompanied by a pantomime of toking a joint (but see {Appendix B}).... - The Holy Trinity of Rock: E-A-B, E-A-B-A.
- A, B, ... (Long time, no C)