This limerick was previously posted incorrectly. The integral limit has been changed.] Here's a limerick I picked up off the net a few years back -

[This limerick was previously posted incorrectly.
The integral limit has been changed.]

Here's a limerick I picked up off the net a few years back - looks better
on paper.

3_
\/3
/
| 2 3 X pi 3_
| z dz X cos(--------) = ln (\/e )
| 9
/
1

Which, of course, translates to:

Integral z-squared dz
from 1 to the cube root of 3
times the cosine
of three pi over 9
equals log of the cube root of 'e'.

And it's correct, too.